fix: hide open with internal ip if force_expose is true
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2 changed files with 7 additions and 5 deletions
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@ -2,7 +2,7 @@
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/* tslint:disable */
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/* tslint:disable */
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/**
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/**
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* Mock Service Worker (1.2.1).
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* Mock Service Worker (1.2.2).
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* @see https://github.com/mswjs/msw
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* @see https://github.com/mswjs/msw
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* - Please do NOT modify this file.
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* - Please do NOT modify this file.
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* - Please do NOT serve this file on production.
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* - Please do NOT serve this file on production.
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@ -84,10 +84,12 @@ export const AppActions: React.FC<IProps> = ({ app, status, localDomain, onInsta
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<IconLock className="text-muted me-2" size={16} />
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<IconLock className="text-muted me-2" size={16} />
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{app.id}.{localDomain}
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{app.id}.{localDomain}
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</DropdownMenuItem>
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</DropdownMenuItem>
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{!app.info.force_expose && (
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<DropdownMenuItem onClick={() => onOpen('local')}>
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<DropdownMenuItem onClick={() => onOpen('local')}>
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<IconLockOff className="text-muted me-2" size={16} />
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<IconLockOff className="text-muted me-2" size={16} />
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{window.location.hostname}:{app.info.port}
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{window.location.hostname}:{app.info.port}
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</DropdownMenuItem>
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</DropdownMenuItem>
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)}
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</DropdownMenuGroup>
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</DropdownMenuGroup>
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</DropdownMenuContent>
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</DropdownMenuContent>
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</DropdownMenu>
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</DropdownMenu>
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