fix: hide open with internal ip if force_expose is true

public/mockServiceWorker.js

@@ -2,7 +2,7 @@
 /* tslint:disable */
 
 /**
- * Mock Service Worker (1.2.1).
+ * Mock Service Worker (1.2.2).
  * @see https://github.com/mswjs/msw
  * - Please do NOT modify this file.
  * - Please do NOT serve this file on production.

src/client/modules/Apps/components/AppActions/AppActions.tsx

@@ -84,10 +84,12 @@ export const AppActions: React.FC<IProps> = ({ app, status, localDomain, onInsta
             <IconLock className="text-muted me-2" size={16} />
             {app.id}.{localDomain}
           </DropdownMenuItem>
-          <DropdownMenuItem onClick={() => onOpen('local')}>
-            <IconLockOff className="text-muted me-2" size={16} />
-            {window.location.hostname}:{app.info.port}
-          </DropdownMenuItem>
+          {!app.info.force_expose && (
+            <DropdownMenuItem onClick={() => onOpen('local')}>
+              <IconLockOff className="text-muted me-2" size={16} />
+              {window.location.hostname}:{app.info.port}
+            </DropdownMenuItem>
+          )}
         </DropdownMenuGroup>
       </DropdownMenuContent>
     </DropdownMenu>