healthcheck: do not interpret exit code 2 as "starting"
Instead reserve exit code 2 to be future proof, document that it should not be used. Implementation-wise, it is considered as unhealthy, but users should not rely on this as it may change in the future. Signed-off-by: Tibor Vass <tibor@docker.com>
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3 changed files with 2 additions and 24 deletions
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@ -41,7 +41,6 @@ const (
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exitStatusHealthy = 0 // Container is healthy
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exitStatusUnhealthy = 1 // Container is unhealthy
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exitStatusStarting = 2 // Container needs more time to start
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)
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// probe implementations know how to run a particular type of probe.
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@ -127,12 +126,10 @@ func handleProbeResult(d *Daemon, c *container.Container, result *types.Healthch
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if result.ExitCode == exitStatusHealthy {
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h.FailingStreak = 0
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h.Status = types.Healthy
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} else if result.ExitCode == exitStatusStarting && c.State.Health.Status == types.Starting {
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// The container is not ready yet. Remain in the starting state.
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} else {
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// Failure (including invalid exit code)
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h.FailingStreak++
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if c.State.Health.FailingStreak >= retries {
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if h.FailingStreak >= retries {
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h.Status = types.Unhealthy
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}
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// Else we're starting or healthy. Stay in that state.
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@ -94,22 +94,6 @@ func TestHealthStates(t *testing.T) {
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handleResult(c.State.StartedAt.Add(3*time.Second), 1)
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expect("health_status: unhealthy")
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// starting -> starting -> starting ->
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// healthy -> starting (invalid transition)
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reset(c)
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handleResult(c.State.StartedAt.Add(20*time.Second), 2)
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handleResult(c.State.StartedAt.Add(40*time.Second), 2)
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if c.State.Health.Status != types.Starting {
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t.Errorf("Expecting starting, but got %#v\n", c.State.Health.Status)
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}
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handleResult(c.State.StartedAt.Add(50*time.Second), 0)
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expect("health_status: healthy")
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handleResult(c.State.StartedAt.Add(60*time.Second), 2)
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expect("health_status: unhealthy")
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// Test retries
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reset(c)
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@ -1524,10 +1524,7 @@ The possible values are:
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- 0: success - the container is healthy and ready for use
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- 1: unhealthy - the container is not working correctly
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- 2: starting - the container is not ready for use yet, but is working correctly
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If the probe returns 2 ("starting") when the container has already moved out of the
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"starting" state then it is treated as "unhealthy" instead.
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- 2: reserved - do not use this exit code
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For example, to check every five minutes or so that a web-server is able to
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serve the site's main page within three seconds:
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