1aea8f116b
This allows you to iterate a subtree and get a callback for every node where is<T>(node) == true. This makes for quite pleasant DOM traversal.
56 lines
1.4 KiB
C++
56 lines
1.4 KiB
C++
#include <AK/StringBuilder.h>
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#include <LibHTML/DOM/HTMLFormElement.h>
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#include <LibHTML/DOM/HTMLInputElement.h>
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#include <LibHTML/Frame.h>
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#include <LibHTML/HtmlView.h>
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HTMLFormElement::HTMLFormElement(Document& document, const String& tag_name)
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: HTMLElement(document, tag_name)
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{
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}
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HTMLFormElement::~HTMLFormElement()
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{
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}
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void HTMLFormElement::submit()
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{
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if (action().is_null()) {
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dbg() << "Unsupported form action ''";
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return;
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}
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if (method().to_lowercase() != "get") {
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dbg() << "Unsupported form method '" << method() << "'";
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return;
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}
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URL url(document().complete_url(action()));
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struct NameAndValue {
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String name;
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String value;
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};
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Vector<NameAndValue> parameters;
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for_each_in_subtree_of_type<HTMLInputElement>([&](auto& node) {
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auto& input = to<HTMLInputElement>(node);
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if (!input.name().is_null())
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parameters.append({ input.name(), input.value() });
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return IterationDecision::Continue;
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});
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StringBuilder builder;
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for (int i = 0; i < parameters.size(); ++i) {
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builder.append(parameters[i].name);
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builder.append('=');
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builder.append(parameters[i].value);
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if (i != parameters.size() - 1)
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builder.append('&');
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}
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url.set_query(builder.to_string());
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// FIXME: We shouldn't let the form just do this willy-nilly.
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document().frame()->html_view()->load(url);
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}
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