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HackStudio: Do not spawn an intermediary shell

The Shell also puts each command into its own process group,
which interferes with us trying to do the same here. We don't
really need the shell here anyway, but it means we'll have to
do command splitting ourselves.
Sergey Bugaev 5 лет назад
Родитель
Сommit
1f5001c581
1 измененных файлов с 10 добавлено и 6 удалено
  1. 10 6
      DevTools/HackStudio/TerminalWrapper.cpp

+ 10 - 6
DevTools/HackStudio/TerminalWrapper.cpp

@@ -103,13 +103,17 @@ void TerminalWrapper::run_command(const String& command)
             perror("ioctl(TIOCSCTTY)");
             exit(1);
         }
-        const char* args[4] = { "/bin/Shell", nullptr, nullptr, nullptr };
-        if (!command.is_empty()) {
-            args[1] = "-c";
-            args[2] = command.characters();
+
+        setenv("TERM", "xterm", true);
+        setenv("PATH", "/bin:/usr/bin:/usr/local/bin", true);
+
+        auto parts = command.split(' ');
+        ASSERT(!parts.is_empty());
+        const char** args = (const char**) calloc(parts.size() + 1, sizeof(const char*));
+        for (int i = 0; i < parts.size(); i++) {
+            args[i] = parts[i].characters();
         }
-        const char* envs[] = { "TERM=xterm", "PATH=/bin:/usr/bin:/usr/local/bin", nullptr };
-        rc = execve("/bin/Shell", const_cast<char**>(args), const_cast<char**>(envs));
+        rc = execvp(args[0], const_cast<char**>(args));
         if (rc < 0) {
             perror("execve");
             exit(1);